Answer by Quasímodo for Show all lines before a match
To print all lines before the match,perl -pe 'exit if /foo/' fileawk '/foo/{exit} 1' file
View ArticleAnswer by user.dz for Show all lines before a match
FreeBSD (including MacOS) version does have such feature.Well -B -1 works, it shows all the lines before the match from the beginning of the file.... | grep -B -1 -- "foo"Same for -A -1 , it shows all...
View ArticleAnswer by ks1322 for Show all lines before a match
Show ALL lines before a matchYou can use large enough number for -B option of grep. For example if your know that input size is no more than 999 you can use it with -B option:... | grep -B 999 -- "foo"
View ArticleAnswer by JoL for Show all lines before a match
Current solutions except schrodigerscatcuriosity's print the file contents even when there's no match. schrodigerscatcuriosity's involves using tac and so requires reading the whole input before...
View ArticleAnswer by Quasímodo for Show all lines before a match
Including the match,sed '/foo/q' fileIt is better to quit sed as soon as a match is found, otherwise sed would keep reading the file and wasting your time, which would be considerable for large...
View ArticleAnswer by Cyrus for Show all lines before a match
With GNU sed. Print all lines, from the first to the line with the required string.sed '0,/foo/!d' file
View ArticleAnswer by schrodingerscatcuriosity for Show all lines before a match
Here's a solution with sed, given the content of file.txt:barbazmoofooloozoocommand including patterntac file.txt | sed -n '/foo/,$p' | tacoutputbarbazmoofooexcluding patterntac file.txt | sed -n -e...
View ArticleShow all lines before a match
I want to show all lines before a match, not only 10, or 7, or 14 for example, as explained in How do I fetch lines before/after the grep result in bash?.How can I do it? It doesn't matter if the...
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